Use std::max_element instead of reimplementing it
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1 changed files with 1 additions and 33 deletions
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@ -26,16 +26,6 @@ int BasisOptimize_print_lvl = 0;
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*/
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static void print_stringTrunc(const char* str, int space, int alignment);
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//! Finds the location of the maximum component in a vector *x*
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/*!
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* @param x Vector to search
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* @param j j <= i < n : i is the range of indices to search in *x*
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* @param n Length of the vector
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*
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* @return index of the greatest value on *x* searched
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*/
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static size_t amax(double* x, size_t j, size_t n);
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size_t Cantera::BasisOptimize(int* usedZeroedSpecies, bool doFormRxn,
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MultiPhase* mphase, std::vector<size_t>& orderVectorSpecies,
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std::vector<size_t>& orderVectorElements,
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@ -167,7 +157,7 @@ size_t Cantera::BasisOptimize(int* usedZeroedSpecies, bool doFormRxn,
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* for the largest remaining species. Return its identity.
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* kk is the raw number. k is the orderVectorSpecies index.
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*/
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kk = amax(DATA_PTR(molNum), 0, nspecies);
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kk = max_element(molNum.begin(), molNum.end()) - molNum.begin();
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for (j = 0; j < nspecies; j++) {
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if (orderVectorSpecies[j] == kk) {
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k = j;
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@ -432,28 +422,6 @@ static void print_stringTrunc(const char* str, int space, int alignment)
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}
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}
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/*
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* Finds the location of the maximum component in a double vector
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* INPUT
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* x(*) - Vector to search
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* j <= i < n : i is the range of indices to search in X(*)
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*
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* RETURN
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* return index of the greatest value on X(*) searched
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*/
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static size_t amax(double* x, size_t j, size_t n)
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{
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size_t largest = j;
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double big = x[j];
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for (size_t i = j + 1; i < n; ++i) {
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if (x[i] > big) {
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largest = i;
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big = x[i];
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}
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}
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return largest;
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}
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size_t Cantera::ElemRearrange(size_t nComponents, const vector_fp& elementAbundances,
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MultiPhase* mphase,
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std::vector<size_t>& orderVectorSpecies,
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